3z+2[2+3(z-1)]=2(3z+4)

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Solution for 3z+2[2+3(z-1)]=2(3z+4) equation:


Simplifying
3z + 2[2 + 3(z + -1)] = 2(3z + 4)

Reorder the terms:
3z + 2[2 + 3(-1 + z)] = 2(3z + 4)
3z + 2[2 + (-1 * 3 + z * 3)] = 2(3z + 4)
3z + 2[2 + (-3 + 3z)] = 2(3z + 4)

Combine like terms: 2 + -3 = -1
3z + 2[-1 + 3z] = 2(3z + 4)
3z + [-1 * 2 + 3z * 2] = 2(3z + 4)
3z + [-2 + 6z] = 2(3z + 4)

Reorder the terms:
-2 + 3z + 6z = 2(3z + 4)

Combine like terms: 3z + 6z = 9z
-2 + 9z = 2(3z + 4)

Reorder the terms:
-2 + 9z = 2(4 + 3z)
-2 + 9z = (4 * 2 + 3z * 2)
-2 + 9z = (8 + 6z)

Solving
-2 + 9z = 8 + 6z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6z' to each side of the equation.
-2 + 9z + -6z = 8 + 6z + -6z

Combine like terms: 9z + -6z = 3z
-2 + 3z = 8 + 6z + -6z

Combine like terms: 6z + -6z = 0
-2 + 3z = 8 + 0
-2 + 3z = 8

Add '2' to each side of the equation.
-2 + 2 + 3z = 8 + 2

Combine like terms: -2 + 2 = 0
0 + 3z = 8 + 2
3z = 8 + 2

Combine like terms: 8 + 2 = 10
3z = 10

Divide each side by '3'.
z = 3.333333333

Simplifying
z = 3.333333333

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